X^2-50x+48=0

Solution for X^2-50x+48=0 equation:

X^2-50X+48=0

a = 1; b = -50; c = +48;
Δ = b2-4ac
Δ = -502-4·1·48
Δ = 2308
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2308}=\sqrt{4*577}=\sqrt{4}*\sqrt{577}=2\sqrt{577}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-50)-2\sqrt{577}}{2*1}=\frac{50-2\sqrt{577}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-50)+2\sqrt{577}}{2*1}=\frac{50+2\sqrt{577}}{2}
$